# Distribute Candies

Given an integer array with **even** length, where different numbers in this array represent different **kinds** of candies. Each number means one candy of the corresponding kind. You need to distribute these candies **equally** in number to brother and sister. Return the maximum number of **kinds** of candies the sister could gain.

**Example 1:**

```
Input:
 candies = [1,1,2,2,3,3]

Output:
 3

Explanation:

There are three different kinds of candies (1, 2 and 3), and two candies for each kind.
Optimal distribution: The sister has candies [1,2,3] and the brother has candies [1,2,3], too. 
The sister has three different kinds of candies.
```

**Example 2:**

```
Input:
 candies = [1,1,2,3]

Output:
 2

Explanation:
 For example, the sister has candies [2,3] and the brother has candies [1,1]. 
The sister has two different kinds of candies, the brother has only one kind of candies.
```

## 题目大意：

给定一组长度为偶数的整数，其中每个数字代表一个糖果的种类标号。

将糖果均分给哥哥和妹妹，返回妹妹可以得到的最大糖果种类数。

**注意：**

1. 数组长度范围\[2, 10,000]，并且为偶数
2. 给定数字范围\[-100,000, 100,000]

## 解题思路：

这道题给我们一堆糖，每种糖的个数不定，分给两个人，让我们求其中一个人能拿到的最大的糖的种类数。那么我们想，如果总共有n个糖，平均分给两个人，每人得到n/2块糖，那么能拿到的最大的糖的种类数也就是n／2种，不可能再多，只可能再少。那么我们要做的就是统计出总共的糖的种类数，如果糖的种类数小于n/2，说明拿不到n/2种糖，最多能拿到的种类数数就是当前糖的总种类数，明白了这点就很容易了，我们利用集合set的自动去重复特性来求出糖的种类数，然后跟n/2比较，取二者之中的较小值返回即可

返回 min( 糖果总数的一半, 糖果种类数 ) 即可

```
class Solution(object):
    def distributeCandies(self, candies):
        """
        :type candies: List[int]
        :rtype: int
        """
        return min(len(candies)/2, len(set(candies)))
```
