# Length of Last Word

Given a stringsconsists of upper/lower-case alphabets and empty space characters`' '`, return the length of last word in the string.

If the last word does not exist, return 0.

**Note:**A word is defined as a character sequence consists of non-space characters only.

For example,\
Givens=`"Hello World"`,\
return`5`.

这道题主要是考虑一下最后是不是空格，方法是倒着找不是空格的字符并计数，如果遇到空格**且计数不是0(如果遇到空格，且count是0，说明input的最后一个char是空格，例如：‘a ’)**，说明最后一个单词已经被计数了，所以可以返回了。

```
class Solution(object):
    def lengthOfLastWord(self, s):
        """
        :type s: str
        :rtype: int
        """
        if len(s) == 0:
            return 0
        count = 0
        for char in reversed(s):
            if char !=' ':
                count += 1
            elif char == ' ' and count != 0:
                return count
        return count
```

第二种方法 先用strip() 消掉首位所有空格，然后用split函数把字符串按照空格分隔好，返回最后那个就行.

注意顺序，先strip，然后再len(l)

```
class Solution(object):
    def lengthOfLastWord(self, s):
        """
        :type s: str
        :rtype: int
        """
        s = s.strip()
        if len(s) == 0:
            return 0
        return len(s.split()[-1])
```