# Delete Node in a Linked List

Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

Supposed the linked list is`1 -> 2 -> 3 -> 4`and you are given the third node with value`3`, the linked list should become`1 -> 2 -> 4`after calling your function.

## 题目大意：

编写一个函数删除单链表中（除末尾节点外）的一个节点，只提供待删除节点。

假如链表是1 -> 2 -> 3 -> 4 给你第3个节点，值为3，则调用你的函数后链表为1 -> 2 -> 4

这道题让我们删除链表的一个节点，更通常不同的是，没有给我们链表的起点，只给我们了一个要删的节点，跟我们以前遇到的情况不太一样，我们之前要删除一个节点的方法是要有其前一个节点的位置，然后将其前一个节点的next连向要删节点的下一个。这道题的处理方法是先把当前节点的值用下一个节点的值覆盖了，然后我们删除下一个节点即可。

```
class Solution(object):
    def deleteNode(self, node):
        """
        :type node: ListNode
        :rtype: void Do not return anything, modify node in-place instead.
        """
        node.val= node.next.val
        node.next = node.next.next
```


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