Max Consecutive Ones

Given a binary array, find the maximum number of consecutive 1s in this array.

Example 1:

Input:
 [1,1,0,1,1,1]

Output:
 3

Explanation:
 The first two digits or the last three digits are consecutive 1s.
    The maximum number of consecutive 1s is 3.

题目大意：

给定一个二进制数组，计算数组中出现的最大连续1的个数。

注意：

• 输入数组只包含0和1

• 数组长度是正整数并且不会超过10000

解题思路：

一趟遍历+计数器

class Solution(object):
    def findMaxConsecutiveOnes(self, nums):
        """
        :type nums: List[int]
        :rtype: int
        """
        maxnumber = 0
        count = 0
        for i in xrange(len(nums)):
            if nums[i] == 1:
                count += 1
                maxnumber = max(maxnumber, count)
            else:
                count = 0
        return maxnumber